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In the diagram below, 
bar(QR) is parallel to 
bar(NO). If 
QR=30,PO=28, and 
PR=20, find the length of 
bar(NO). Figures are not necessarily drawn to scale.

In the diagram below, QR \overline{Q R} is parallel to NO \overline{N O} . If QR=30,PO=28 Q R=30, P O=28 , and PR=20 P R=20 , find the length of NO \overline{N O} . Figures are not necessarily drawn to scale.

Full solution

Q. In the diagram below, QR \overline{Q R} is parallel to NO \overline{N O} . If QR=30,PO=28 Q R=30, P O=28 , and PR=20 P R=20 , find the length of NO \overline{N O} . Figures are not necessarily drawn to scale.
  1. Triangles Similarity: Since QR\overline{QR} is parallel to NO\overline{NO}, and we have a transversal line PRPR, by the properties of parallel lines, triangle PQRPQR is similar to triangle PNOPNO.
  2. Proportional Sides: Using the properties of similar triangles, the sides are proportional. So, QRPR=NOPO\frac{QR}{PR} = \frac{NO}{PO}.
  3. Substitute Values: Substitute the given values into the proportion: 3020=NO28\frac{30}{20} = \frac{NO}{28}.
  4. Simplify Proportion: Simplify the left side of the proportion: 32=NO28\frac{3}{2} = \frac{NO}{28}.
  5. Cross-Multiply: Cross-multiply to solve for NO: 3×28=2×NO.3 \times 28 = 2 \times \text{NO}.
  6. Calculate Multiplication: Calculate the multiplication: 84=2×NO84 = 2 \times NO.
  7. Divide to Find NO: Divide both sides by 22 to find NO: NO=842NO = \frac{84}{2}.
  8. Final Calculation: Calculate the division: NO=42NO = 42.

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