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In the data set below, what are the lower quartile, the median, and the upper quartile?

{:[51,88,86,15,28,33,30]:}
lower quartile =
median 
=
upper quartile 
=
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In the data set below, what are the lower quartile, the median, and the upper quartile?\newline51888615283330 \begin{array}{lllllll}51 & 88 & 86 & 15 & 28 & 33 & 30\end{array} \newlinelower quartile =\newlinemedian = = \newlineupper quartile = = \newlineSubmit

Full solution

Q. In the data set below, what are the lower quartile, the median, and the upper quartile?\newline51888615283330 \begin{array}{lllllll}51 & 88 & 86 & 15 & 28 & 33 & 30\end{array} \newlinelower quartile =\newlinemedian = = \newlineupper quartile = = \newlineSubmit
  1. Arrange Data Set: First, we need to arrange the data set in ascending order to find the quartiles and median.\newlineThe given data set is: {51,88,86,15,28,33,30}\{51,88,86,15,28,33,30\}\newlineArranged in ascending order: 15,28,30,33,51,86,8815, 28, 30, 33, 51, 86, 88
  2. Find Median: Now, we need to find the median of the data set, which is the middle number when the data is ordered.\newlineSince there are 77 numbers, the median is the 44th number.\newlineMedian: 3333
  3. Find Lower Quartile: Next, we find the lower quartile (Q1Q_1), which is the median of the lower half of the data set, excluding the median of the entire data set.\newlineThe lower half of the data set is: 15,28,3015, 28, 30\newlineSince there are 33 numbers, the median of this subset is the 22nd number.\newlineLower quartile (Q1Q_1): 2828
  4. Find Upper Quartile: Finally, we find the upper quartile (Q33), which is the median of the upper half of the data set, excluding the median of the entire data set.\newlineThe upper half of the data set is: 5151, 8686, 8888\newlineSince there are 33 numbers, the median of this subset is the 22nd number.\newlineUpper quartile (Q33): 8686

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