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In the data set below, what are the lower quartile, the median, and the upper quartile?\newline82,82,82,82,82,83,84,86,86,87,8782, 82, 82, 82, 82, 83, 84, 86, 86, 87, 87\newlinelower quartile==__\_\_\newlinemedian==__\_\_\newlineupper quartile==__\_\_

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?\newline82,82,82,82,82,83,84,86,86,87,8782, 82, 82, 82, 82, 83, 84, 86, 86, 87, 87\newlinelower quartile==__\_\_\newlinemedian==__\_\_\newlineupper quartile==__\_\_
  1. Identify the median: Step 11: Identify the median of the data set 82,82,82,82,82,83,84,86,86,87,8782, 82, 82, 82, 82, 83, 84, 86, 86, 87, 87. Since there are 1111 numbers, the median is the 66th number. Calculation: Median =83= 83
  2. Determine lower quartile: Step 22: Determine the lower quartile.\newlineFor the lower quartile, consider the first half of the data set, excluding the median.\newlineFirst half: 82,82,82,82,8282, 82, 82, 82, 82.\newlineCalculation: Lower quartile = 8282 (middle value of the first half)
  3. Determine upper quartile: Step 33: Determine the upper quartile.\newlineFor the upper quartile, consider the second half of the data set, excluding the median.\newlineSecond half: 84,86,86,87,8784, 86, 86, 87, 87.\newlineCalculation: Upper quartile =86= 86 (middle value of the second half)

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