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In the data set below, what are the lower quartile, the median, and the upper quartile?\newline10,10,31,31,52,57,67,71,71,79,87,9210, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92\newlinelower quartile==__\_\_\newlinemedian==__\_\_\newlineupper quartile==__\_\_

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Q. In the data set below, what are the lower quartile, the median, and the upper quartile?\newline10,10,31,31,52,57,67,71,71,79,87,9210, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92\newlinelower quartile==__\_\_\newlinemedian==__\_\_\newlineupper quartile==__\_\_
  1. Identify the median: Step 11: Identify the median of the data set.\newlineData set: 10,10,31,31,52,57,67,71,71,79,87,9210, 10, 31, 31, 52, 57, 67, 71, 71, 79, 87, 92.\newlineSince there are 1212 numbers, the median will be the average of the 66th and 77th numbers.\newlineCalculation: (57+67)/2=62(57 + 67) / 2 = 62.
  2. Identify the lower quartile: Step 22: Identify the lower quartile.\newlineFor the lower quartile, consider the first half of the data set: 10,10,31,31,52,5710, 10, 31, 31, 52, 57.\newlineSince there are 66 numbers, the lower quartile will be the average of the 33rd and 44th numbers.\newlineCalculation: (31+31)/2=31(31 + 31) / 2 = 31.
  3. Identify the upper quartile: Step 33: Identify the upper quartile.\newlineFor the upper quartile, consider the second half of the data set: 67,71,71,79,87,9267, 71, 71, 79, 87, 92.\newlineSince there are 66 numbers, the upper quartile will be the average of the 33rd and 44th numbers.\newlineCalculation: (71+71)/2=71(71 + 71) / 2 = 71.

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