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In March, William saved 
$60 of his pocket money and spent the rest. In April, he saved 
25% less and his spending increased by 
10%. Given that he had the same amount of pocket money each month, how much was William's pocket money?

In March, William saved $60 \$ 60 of his pocket money and spent the rest. In April, he saved 25% 25 \% less and his spending increased by 10% 10 \% . Given that he had the same amount of pocket money each month, how much was William's pocket money?

Full solution

Q. In March, William saved $60 \$ 60 of his pocket money and spent the rest. In April, he saved 25% 25 \% less and his spending increased by 10% 10 \% . Given that he had the same amount of pocket money each month, how much was William's pocket money?
  1. March Savings: In March, William saved $60\$60. This is the amount he didn't spend.
  2. April Savings: In April, he saved 25%25\% less than in March. So, he saved 75%75\% of what he saved in March.\newlineCalculation: 75%75\% of $60\$60 = 0.75×$60=$450.75 \times \$60 = \$45.
  3. April Spending Increase: His spending in April increased by 10%10\% compared to March. If SS is his spending in March, then his spending in April is S+0.10S=1.10SS + 0.10S = 1.10S.
  4. Pocket Money Calculation: Since his pocket money is the same each month, let's call it PP. In March, he saved $60\$60, so he spent P$60P - \$60.
  5. Equation Setup: In April, he saved $45\$45, so he spent P$45P - \$45. But this amount is 10%10\% more than what he spent in March.\newlineCalculation: P$45=1.10(P$60)P - \$45 = 1.10(P - \$60).
  6. Equation Solution: Now we solve the equation for PP.P$(45)=1.10(P$(60))P - \$(45) = 1.10(P - \$(60))P$(45)=1.10P$(66)P - \$(45) = 1.10P - \$(66)Subtract PP from both sides: $(45)=0.10P$(66)- \$(45) = 0.10P - \$(66)Add $(66)\$(66) to both sides: $(21)=0.10P\$(21) = 0.10PDivide both sides by 0.100.10: P=$(21)/0.10P = \$(21) / 0.10

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