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In 
/_\DEF,DE=5 and 
EF=8. If the length of the third side is an integer, what is the greatest possible value for 
DF ?


5+8=12

22) In DEF,DE=5 \triangle D E F, D E=5 and EF=8 E F=8 . If the length of the third side is an integer, what is the greatest possible value for DF D F ?\newline5+8=12 5+8=12

Full solution

Q. 22) In DEF,DE=5 \triangle D E F, D E=5 and EF=8 E F=8 . If the length of the third side is an integer, what is the greatest possible value for DF D F ?\newline5+8=12 5+8=12
  1. Triangle Inequality Theorem: We know that in any triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
  2. Applying Inequality to DE + EF: So, DE+EF>DFDE + EF > DF, which means 5+8>DF5 + 8 > DF.
  3. Calculating Upper Limit for DF: That gives us 13>DF.13 > \text{DF}.
  4. Difference Inequality for EFDEEF - DE: But we also know that the difference of the lengths of any two sides must be less than the length of the third side.
  5. Calculating Lower Limit for DF: So, EFDE<DFEF - DE < DF, which means 85<DF8 - 5 < DF.
  6. Determining Range for DF: That gives us 3<DF.3 < \text{DF}.
  7. Maximum Integer Value for DF: Therefore, DFDF must be greater than 33 and less than 1313.
  8. Maximum Integer Value for DF: Therefore, DFDF must be greater than 33 and less than 1313. Since DFDF is an integer, the greatest possible integer value for DFDF is 1212.

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