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In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 13\frac{1}{3}, and the probability that events AA and BB both occur is 15\frac{1}{5}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____

Full solution

Q. In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 13\frac{1}{3}, and the probability that events AA and BB both occur is 15\frac{1}{5}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____
  1. Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(AB)P(A|B): We know P(A and B)=15P(A \text{ and } B) = \frac{1}{5} and P(B)=13P(B) = \frac{1}{3}. So, P(AB)=1513P(A|B) = \frac{\frac{1}{5}}{\frac{1}{3}}.
  3. Divide Fractions: To divide fractions, we multiply by the reciprocal of the divisor. So, P(AB)=15×31=35P(A|B) = \frac{1}{5} \times \frac{3}{1} = \frac{3}{5}.

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