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In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 3263\frac{32}{63}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 3263\frac{32}{63}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(89)×(47)P(A) \times P(B) = \left(\frac{8}{9}\right) \times \left(\frac{4}{7}\right)
  3. Perform Multiplication: Now, do the multiplication.\newline(89)×(47)=3263(\frac{8}{9}) \times (\frac{4}{7}) = \frac{32}{63}
  4. Compare Product with P(A and B)P(A \text{ and } B): Compare the product of P(A)P(A) and P(B)P(B) with P(A and B)P(A \text{ and } B). Since P(A and B)P(A \text{ and } B) is also 3263\frac{32}{63}, the product of P(A)P(A) and P(B)P(B) is equal to P(A and B)P(A \text{ and } B).
  5. Confirm Independence of Events: Since P(A)×P(B)=P(A and B)P(A) \times P(B) = P(A \text{ and } B), events AA and BB are independent.

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