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In an experiment, the probability that event AA occurs is 49\frac{4}{9}, the probability that event BB occurs is 34\frac{3}{4}, and the probability that events AA and BB both occur is 29\frac{2}{9}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 49\frac{4}{9}, the probability that event BB occurs is 34\frac{3}{4}, and the probability that events AA and BB both occur is 29\frac{2}{9}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B).P(A)×P(B)=(49)×(34)P(A) \times P(B) = \left(\frac{4}{9}\right) \times \left(\frac{3}{4}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(49)×(34)=1236(\frac{4}{9}) \times (\frac{3}{4}) = \frac{12}{36}
  4. Simplify Fraction: Simplify the fraction 1236\frac{12}{36} to its lowest terms.\newline1236=13\frac{12}{36} = \frac{1}{3}
  5. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=29P(A \text{ and } B) = \frac{2}{9}\newlineP(A)×P(B)=13P(A) \times P(B) = \frac{1}{3}
  6. Determine Independence: Since 29\frac{2}{9} is not equal to 13\frac{1}{3}, events AA and BB are not independent.

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