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In an experiment, the probability that event AA occurs is 18\frac{1}{8} and the probability that event BB occurs is 78\frac{7}{8}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 18\frac{1}{8} and the probability that event BB occurs is 78\frac{7}{8}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.
  1. Question Prompt: question_prompt: What's the probability that both event AA and event BB happen if they're independent?
  2. Calculation of P(A and B): P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B) cuz they're independent, so let's multiply the probabilities of AA and BB.
  3. Calculate P(A)P(A) and P(B)P(B): P(A)=18P(A) = \frac{1}{8} and P(B)=78P(B) = \frac{7}{8}, so P(A and B)=18×78P(A \text{ and } B) = \frac{1}{8} \times \frac{7}{8}.
  4. Multiply Probabilities: Now, do the math: 18×78=764\frac{1}{8} \times \frac{7}{8} = \frac{7}{64}.
  5. Final Probability: No need to simplify, 7/647/64 is already as simple as it gets.

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