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In an experiment, the probability that event AA occurs is 17\frac{1}{7}, the probability that event BB occurs is 34\frac{3}{4}, and the probability that events AA and BB both occur is 328\frac{3}{28}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 17\frac{1}{7}, the probability that event BB occurs is 34\frac{3}{4}, and the probability that events AA and BB both occur is 328\frac{3}{28}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Individual Probabilities: First, let's find the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(17)×(34)P(A) \times P(B) = \left(\frac{1}{7}\right) \times \left(\frac{3}{4}\right)
  3. Calculate Product: Now, calculate the product.\newline(17)×(34)=328(\frac{1}{7}) \times (\frac{3}{4}) = \frac{3}{28}
  4. Compare Probabilities: Next, we compare this product to the probability of AA and BB both occurring, which is given as 328\frac{3}{28}.
  5. Verify Equality: Since P(A and B)=328P(A \text{ and } B) = \frac{3}{28} and P(A)×P(B)=328P(A) \times P(B) = \frac{3}{28}, the probabilities are equal.
  6. Conclusion: Therefore, events AA and BB are independent because the product of their individual probabilities equals the probability of them both occurring.

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