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In an experiment, the probability that event $A$ occurs is $\frac{4}{9}$ , the probability that event $B$ occurs is $\frac{5}{7}$ , and the probability that events $A$ and $B$ both occur is $\frac{3}{8}$ . $\newline$ What is the probability that $A$ occurs given that $B$ occurs? $\newline$ Simplify any fractions. $\newline$ ____ $\newline$

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Find conditional probabilities

Full solution

Q. In an experiment, the probability that event

A

occurs is

\frac{4}{9}

, the probability that event

B

occurs is

\frac{5}{7}

, and the probability that events

A

and

B

both occur is

\frac{3}{8}

.

\newline

What is the probability that

A

occurs given that

B

occurs?

\newline

Simplify any fractions.

\newline

____

\newline

Use Conditional Probability Formula: To find the probability that $A$ occurs given that $B$ occurs, we use the formula for conditional probability: $P(A|B) = \frac{P(A \text{ and } B)}{P(B)}$ .
Calculate $P(A|B)$ : We know $P(A \text{ and } B) = \frac{3}{8}$ and $P(B) = \frac{5}{7}$ . So, $P(A|B) = \frac{\frac{3}{8}}{\frac{5}{7}}$ .
Multiply Fractions: To divide the fractions, we multiply by the reciprocal of the second fraction: $(\frac{3}{8}) \times (\frac{7}{5})$ .
Simplify Result: Now, multiply the numerators and the denominators: $(3 \times 7) / (8 \times 5)$ .
Simplify Result: Now, multiply the numerators and the denominators: $(3 \times 7) / (8 \times 5)$ .This gives us $21/40$ . So, $P(A|B) = 21/40$ .

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\newline

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\newline

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\newline

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\newline

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\newline

Write your answer as a decimal rounded to the nearest thousandth.

\newline

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\newline

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