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In an experiment, the probability that event AA occurs is 38\frac{3}{8}, the probability that event BB occurs is 38\frac{3}{8}, and the probability that events AA and BB both occur is 964\frac{9}{64}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. In an experiment, the probability that event AA occurs is 38\frac{3}{8}, the probability that event BB occurs is 38\frac{3}{8}, and the probability that events AA and BB both occur is 964\frac{9}{64}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(38)×(38)=964.P(A) \times P(B) = \left(\frac{3}{8}\right) \times \left(\frac{3}{8}\right) = \frac{9}{64}.
  3. Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B): Now, compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).P(A and B)=964P(A \text{ and } B) = \frac{9}{64}, and we just calculated P(A)×P(B)=964P(A) \times P(B) = \frac{9}{64}.
  4. Verify Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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