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In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 16\frac{1}{6}, and the probability that events AA and BB both occur is 17\frac{1}{7}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 16\frac{1}{6}, and the probability that events AA and BB both occur is 17\frac{1}{7}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Substitute Values: We know P(A and B)=17P(A \text{ and } B) = \frac{1}{7} and P(B)=16P(B) = \frac{1}{6}, so we plug these values into the formula: P(AB)=1716P(A|B) = \frac{\frac{1}{7}}{\frac{1}{6}}.
  3. Calculate Probability: Now we calculate P(AB)P(A|B) by multiplying the numerator by the reciprocal of the denominator: (17)×(61)=67(\frac{1}{7}) \times (\frac{6}{1}) = \frac{6}{7}.

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