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In an experiment, the probability that event AA occurs is 35\frac{3}{5}, the probability that event BB occurs is 78\frac{7}{8}, and the probability that events AA and BB both occur is 2140\frac{21}{40}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 35\frac{3}{5}, the probability that event BB occurs is 78\frac{7}{8}, and the probability that events AA and BB both occur is 2140\frac{21}{40}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(35)×(78)P(A) \times P(B) = \left(\frac{3}{5}\right) \times \left(\frac{7}{8}\right)
  3. Perform Multiplication: Now, do the multiplication. (35)×(78)=2140(\frac{3}{5}) \times (\frac{7}{8}) = \frac{21}{40}
  4. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=2140P(A \text{ and } B) = \frac{21}{40} and P(A)×P(B)=2140P(A) \times P(B) = \frac{21}{40}, they are equal.
  5. Determine Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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