Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 2027\frac{20}{27}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 2027\frac{20}{27}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no
  1. Calculate Probabilities: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Multiply Probabilities: First, calculate P(A)×P(B)P(A) \times P(B).\newlineP(A)=89P(A) = \frac{8}{9} and P(B)=56P(B) = \frac{5}{6}.\newlineSo, P(A)×P(B)=(89)×(56)P(A) \times P(B) = \left(\frac{8}{9}\right) \times \left(\frac{5}{6}\right).
  3. Simplify Fraction: Now, do the multiplication.\newline(89)×(56)=4054(\frac{8}{9}) \times (\frac{5}{6}) = \frac{40}{54}.\newlineBut wait, we can simplify this fraction by dividing both numerator and denominator by 22.\newlineSo, 4054\frac{40}{54} simplifies to 2027\frac{20}{27}.
  4. Compare Probabilities: Next, compare P(A)×P(B)P(A) \times P(B) with P(A and B)P(A \text{ and } B). We found P(A)×P(B)=2027P(A) \times P(B) = \frac{20}{27}, and we're given P(A and B)=2027P(A \text{ and } B) = \frac{20}{27}.
  5. Determine Independence: Since P(A)×P(B)P(A) \times P(B) is equal to P(A and B)P(A \text{ and } B), events AA and BB are independent.

More problems from Identify independent events