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In an experiment, the probability that event AA occurs is 58\frac{5}{8}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 58\frac{5}{8}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Identify Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(A and B)P(A \text{ and } B) and P(B)P(B): We know P(A and B)=15P(A \text{ and } B) = \frac{1}{5} and P(B)=47P(B) = \frac{4}{7}. So, P(AB)=1547P(A|B) = \frac{\frac{1}{5}}{\frac{4}{7}}.
  3. Apply Division of Fractions: To divide these fractions, we multiply by the reciprocal of the second fraction: (15)×(74)(\frac{1}{5}) \times (\frac{7}{4}).
  4. Multiply Numerators and Denominators: Now, multiply the numerators and denominators: (1×7)/(5×4)=7/20(1 \times 7) / (5 \times 4) = 7/20.

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