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In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 35\frac{3}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 35\frac{3}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(AB)P(A|B): We know P(A and B)=35P(A \text{ and } B) = \frac{3}{5} and P(B)=57P(B) = \frac{5}{7}. So, P(AB)=3557P(A|B) = \frac{\frac{3}{5}}{\frac{5}{7}}.
  3. Divide Fractions: To divide these fractions, we multiply by the reciprocal of the second fraction: (35)×(75)(\frac{3}{5}) \times (\frac{7}{5}).

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