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In an experiment, the probability that event AA occurs is 15\frac{1}{5}, the probability that event BB occurs is 14\frac{1}{4}, and the probability that events AA and BB both occur is 120\frac{1}{20}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 15\frac{1}{5}, the probability that event BB occurs is 14\frac{1}{4}, and the probability that events AA and BB both occur is 120\frac{1}{20}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, let's find the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(15)×(14)P(A) \times P(B) = \left(\frac{1}{5}\right) \times \left(\frac{1}{4}\right)
  3. Compare Product to Joint Probability: Calculating the product gives us: 1514=120\frac{1}{5} * \frac{1}{4} = \frac{1}{20}
  4. Conclusion of Independence: Now, we compare this product to the probability of A and B occurring together, which is given as 120\frac{1}{20}.
  5. Conclusion of Independence: Now, we compare this product to the probability of A and B occurring together, which is given as 120\frac{1}{20}.Since P(A and B)=P(A)×P(B)=120P(A \text{ and } B) = P(A) \times P(B) = \frac{1}{20}, the events A and B are independent.

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