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In an experiment, the probability that event AA occurs is 19\frac{1}{9}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 121\frac{1}{21}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 19\frac{1}{9}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 121\frac{1}{21}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B).P(A)×P(B)=19×37P(A) \times P(B) = \frac{1}{9} \times \frac{3}{7}
  3. Perform Multiplication: Now, do the multiplication.\newline(19)×(37)=363(\frac{1}{9}) \times (\frac{3}{7}) = \frac{3}{63}
  4. Simplify Fraction: Simplify the fraction 363\frac{3}{63}. 363=121\frac{3}{63} = \frac{1}{21}
  5. Compare Results: Compare the result with P(A and B)P(A \text{ and } B). Since P(A and B)P(A \text{ and } B) is also 121\frac{1}{21}, this means P(A)×P(B)=P(A and B)P(A) \times P(B) = P(A \text{ and } B).
  6. Confirm Independence: Since P(A)×P(B)P(A) \times P(B) equals P(A and B)P(A \text{ and } B), events AA and BB are independent.

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