Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 15\frac{1}{5}, and the probability that events AA and BB both occur is 16\frac{1}{6}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 15\frac{1}{5}, and the probability that events AA and BB both occur is 16\frac{1}{6}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Use Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(AB)P(A|B): We know P(A and B)=16P(A \text{ and } B) = \frac{1}{6} and P(B)=15P(B) = \frac{1}{5}. So, P(AB)=1615P(A|B) = \frac{\frac{1}{6}}{\frac{1}{5}}.
  3. Divide Fractions: Now, we calculate P(AB)P(A|B) by dividing the fractions: (16)÷(15)=(16)×(51)=56(\frac{1}{6}) \div (\frac{1}{5}) = (\frac{1}{6}) \times (\frac{5}{1}) = \frac{5}{6}.

More problems from Find conditional probabilities