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In an experiment, the probability that event AA occurs is 12\frac{1}{2}, the probability that event BB occurs is 78\frac{7}{8}, and the probability that events AA and BB both occur is 716\frac{7}{16}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 12\frac{1}{2}, the probability that event BB occurs is 78\frac{7}{8}, and the probability that events AA and BB both occur is 716\frac{7}{16}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: Calculate P(A)×P(B)P(A) \times P(B): (12)×(78)=716(\frac{1}{2}) \times (\frac{7}{8}) = \frac{7}{16}.
  3. Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B): Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B): Since P(A and B)P(A \text{ and } B) is 716\frac{7}{16} and P(A)×P(B)P(A) \times P(B) is also 716\frac{7}{16}, they are equal.
  4. Confirm Independence: Since P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B), events AA and BB are independent.

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