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In an experiment, the probability that event AA occurs is 23\frac{2}{3}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 16\frac{1}{6}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 23\frac{2}{3}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 16\frac{1}{6}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(23)×(12)P(A) \times P(B) = \left(\frac{2}{3}\right) \times \left(\frac{1}{2}\right)
  3. Perform Multiplication: Perform the multiplication.\newline(23)×(12)=26=13(\frac{2}{3}) \times (\frac{1}{2}) = \frac{2}{6} = \frac{1}{3}
  4. Compare Probabilities: Now, compare the product of P(A)P(A) and P(B)P(B) with P(A and B)P(A \text{ and } B).\newlineP(A and B)=16P(A \text{ and } B) = \frac{1}{6}\newlineP(A)×P(B)=13P(A) \times P(B) = \frac{1}{3}
  5. Determine Independence: Since P(A and B)P(A)×P(B)P(A \text{ and } B) \neq P(A) \times P(B), events AA and BB are not independent.

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