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In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 58\frac{5}{8}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 58\frac{5}{8}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Use Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Identify Given Probabilities: We know P(A and B)=58P(A \text{ and } B) = \frac{5}{8} and P(B)=58P(B) = \frac{5}{8}.
  3. Calculate Conditional Probability: Now, let's plug these values into the formula: P(AB)=58/58P(A|B) = \frac{5}{8} / \frac{5}{8}.
  4. Simplify Fraction: Simplify the fraction: (58)/(58)=1(\frac{5}{8}) / (\frac{5}{8}) = 1.

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