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In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 38\frac{3}{8}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 38\frac{3}{8}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Use Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(AB)P(A|B): We know P(A and B)=38P(A \text{ and } B) = \frac{3}{8} and P(B)=37P(B) = \frac{3}{7}. So, P(AB)=3837P(A|B) = \frac{\frac{3}{8}}{\frac{3}{7}}.
  3. Simplify the Fraction: Now, we simplify the fraction: P(AB)=(38)×(73)=2124.P(A|B) = \left(\frac{3}{8}\right) \times \left(\frac{7}{3}\right) = \frac{21}{24}.

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