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In an experiment, the probability that event AA occurs is 34\frac{3}{4}, the probability that event BB occurs is 13\frac{1}{3}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 34\frac{3}{4}, the probability that event BB occurs is 13\frac{1}{3}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: Calculate the product of P(A)P(A) and P(B)P(B): P(A)×P(B)=34×13P(A) \times P(B) = \frac{3}{4} \times \frac{1}{3}.
  3. Perform Multiplication: Perform the multiplication: (34)×(13)=312=14(\frac{3}{4}) \times (\frac{1}{3}) = \frac{3}{12} = \frac{1}{4}.
  4. Compare Product with P(A and B)P(A \text{ and } B): Compare the product of P(A)×P(B)P(A) \times P(B) with P(A and B)P(A \text{ and } B): 14\frac{1}{4} is not equal to 18\frac{1}{8}.
  5. Conclusion: Since P(A)×P(B)P(A) \times P(B) does not equal P(A and B)P(A \text{ and } B), events AA and BB are not independent.

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