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In an experiment, the probability that event AA occurs is 18\frac{1}{8}, the probability that event BB occurs is 27\frac{2}{7}, and the probability that events AA and BB both occur is 128\frac{1}{28}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 18\frac{1}{8}, the probability that event BB occurs is 27\frac{2}{7}, and the probability that events AA and BB both occur is 128\frac{1}{28}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(18)×(27)P(A) \times P(B) = \left(\frac{1}{8}\right) \times \left(\frac{2}{7}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(18)×(27)=256(\frac{1}{8}) \times (\frac{2}{7}) = \frac{2}{56}
  4. Simplify Fraction: Simplify the fraction 256\frac{2}{56}. 256=128\frac{2}{56} = \frac{1}{28}
  5. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=128P(A \text{ and } B) = \frac{1}{28} and P(A)×P(B)=128P(A) \times P(B) = \frac{1}{28}, they are equal.
  6. Confirm Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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