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In an experiment, the probability that event AA occurs is 78\frac{7}{8}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 37\frac{3}{7}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____

Full solution

Q. In an experiment, the probability that event AA occurs is 78\frac{7}{8}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 37\frac{3}{7}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____
  1. Use Formula: To find the probability that A occurs given that B occurs, we use the formula P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(A and B)P(A \text{ and } B): We know P(A and B)=37P(A \text{ and } B) = \frac{3}{7} and P(B)=12P(B) = \frac{1}{2}.
  3. Calculate P(AB)P(A|B): Now we calculate P(AB)=37/12P(A|B) = \frac{3}{7} / \frac{1}{2}.
  4. Multiply Fractions: To divide by a fraction, we multiply by its reciprocal. So, P(AB)=37×21P(A|B) = \frac{3}{7} \times \frac{2}{1}.
  5. Final Probability Calculation: Multiplying the fractions, we get P(AB)=3×27×1=67P(A|B) = \frac{3 \times 2}{7 \times 1} = \frac{6}{7}.

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