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In an experiment, the probability that event AA occurs is 27\frac{2}{7}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 1049\frac{10}{49}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 27\frac{2}{7}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 1049\frac{10}{49}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Calculate Product: Calculate the product of the individual probabilities of AA and BB.P(A)×P(B)=(27)×(57)P(A) \times P(B) = \left(\frac{2}{7}\right) \times \left(\frac{5}{7}\right)
  2. Perform Multiplication: Perform the multiplication to find the product.\newline(27)×(57)=1049(\frac{2}{7}) \times (\frac{5}{7}) = \frac{10}{49}
  3. Compare Probabilities: Compare the product of P(A)P(A) and P(B)P(B) with the probability of AA and BB occurring together.\newlineSince P(A and B)=1049P(A \text{ and } B) = \frac{10}{49} and P(A)×P(B)=1049P(A) \times P(B) = \frac{10}{49}, the probabilities are equal.
  4. Conclude Independence: Conclude whether AA and BB are independent based on the comparison. Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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