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In an experiment, the probability that event $A$ occurs is $\frac{4}{9}$ and the probability that event $B$ occurs is $\frac{8}{9}$ . If $A$ and $B$ are independent events, what is the probability that $A$ and $B$ both occur? $\newline$ Simplify any fractions.

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Independence and conditional probability

Full solution

Q. In an experiment, the probability that event

A

occurs is

\frac{4}{9}

and the probability that event

B

occurs is

\frac{8}{9}

. If

A

and

B

are independent events, what is the probability that

A

and

B

both occur?

\newline

Simplify any fractions.

Multiply probabilities of A and B: Since $A$ and $B$ are independent, multiply the probabilities of $A$ and $B$ to find the probability of both occurring: $P(A \text{ and } B) = P(A) \times P(B)$ .
Calculate $P(A \text{ and } B)$ : Calculate $P(A \text{ and } B) = \frac{4}{9} \times \frac{8}{9}$ . This equals $\frac{32}{81}$ .
No need to simplify: There's no need to simplify $\frac{32}{81}$ since it's already in its simplest form.

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