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In an experiment, the probability that event AA occurs is 12\frac{1}{2} and the probability that event BB occurs is 49\frac{4}{9}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 12\frac{1}{2} and the probability that event BB occurs is 49\frac{4}{9}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.
  1. Identify Independence: P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B) cuz they're independent, so we gotta multiply the probabilities of AA and BB.
  2. Calculate Individual Probabilities: P(A)=12P(A) = \frac{1}{2} and P(B)=49P(B) = \frac{4}{9}, so P(A and B)=12×49P(A \text{ and } B) = \frac{1}{2} \times \frac{4}{9}.
  3. Multiply Probabilities: Now we do the math: 12×49=418\frac{1}{2} \times \frac{4}{9} = \frac{4}{18}.
  4. Simplify Fraction: We can simplify 418\frac{4}{18} by dividing both the numerator and the denominator by 22.
  5. Final Result: After simplifying, we get 29\frac{2}{9}.

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