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In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 49\frac{4}{9}, and the probability that events AA and BB both occur is 37\frac{3}{7}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____

Full solution

Q. In an experiment, the probability that event AA occurs is 89\frac{8}{9}, the probability that event BB occurs is 49\frac{4}{9}, and the probability that events AA and BB both occur is 37\frac{3}{7}.\newlineWhat is the probability that AA occurs given that BB occurs?\newlineSimplify any fractions.\newline____
  1. Use Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Identify Given Probabilities: We know P(A and B)=37P(A \text{ and } B) = \frac{3}{7} and P(B)=49P(B) = \frac{4}{9}. So, P(AB)=3749P(A|B) = \frac{\frac{3}{7}}{\frac{4}{9}}.
  3. Calculate P(AB)P(A|B): To divide the fractions, we multiply by the reciprocal of the second fraction: (37)×(94)(\frac{3}{7}) \times (\frac{9}{4}).
  4. Multiply Fractions: Now, multiply the numerators and the denominators: (3×9)/(7×4)(3 \times 9) / (7 \times 4).
  5. Simplify Fraction: This gives us 2728\frac{27}{28} as the simplified fraction.

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