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In an experiment, the probability that event AA occurs is 13\frac{1}{3}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 13\frac{1}{3}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Identify Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(A and B)P(A \text{ and } B) and P(B)P(B): We know P(A and B)=15P(A \text{ and } B) = \frac{1}{5} and P(B)=58P(B) = \frac{5}{8}. So, P(AB)=1558P(A|B) = \frac{\frac{1}{5}}{\frac{5}{8}}.
  3. Apply Formula for P(AB)P(A|B): To divide the fractions, we multiply by the reciprocal of the second fraction: (15)×(85)(\frac{1}{5}) \times (\frac{8}{5}).
  4. Simplify Fraction Calculation: Now, multiply the numerators and denominators: 1×85×5=825\frac{1 \times 8}{5 \times 5} = \frac{8}{25}.

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