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In an experiment, the probability that event AA occurs is 47\frac{4}{7}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 17\frac{1}{7}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 47\frac{4}{7}, the probability that event BB occurs is 12\frac{1}{2}, and the probability that events AA and BB both occur is 17\frac{1}{7}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(47)×(12)P(A) \times P(B) = \left(\frac{4}{7}\right) \times \left(\frac{1}{2}\right)
  3. Compare Product to Joint Probability: Now, do the multiplication.\newline(47)×(12)=414=27(\frac{4}{7}) \times (\frac{1}{2}) = \frac{4}{14} = \frac{2}{7}
  4. Conclusion: Compare this product to the probability of AA and BB both occurring, which is given as 17\frac{1}{7}.P(A and B)=17P(A \text{ and } B) = \frac{1}{7}
  5. Conclusion: Compare this product to the probability of AA and BB both occurring, which is given as 17\frac{1}{7}.P(A and B)=17P(A \text{ and } B) = \frac{1}{7}Since 27\frac{2}{7} is not equal to 17\frac{1}{7}, the product of P(A)P(A) and P(B)P(B) is not equal to P(A and B)P(A \text{ and } B). Therefore, events AA and BB are not independent.

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