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In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 14\frac{1}{4}, and the probability that events AA and BB both occur is 528\frac{5}{28}. \newlineAre AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. In an experiment, the probability that event AA occurs is 57\frac{5}{7}, the probability that event BB occurs is 14\frac{1}{4}, and the probability that events AA and BB both occur is 528\frac{5}{28}. \newlineAre AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(57)×(14)P(A) \times P(B) = \left(\frac{5}{7}\right) \times \left(\frac{1}{4}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(57)×(14)=528(\frac{5}{7}) \times (\frac{1}{4}) = \frac{5}{28}
  4. Compare Results: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=528P(A \text{ and } B) = \frac{5}{28} and P(A)×P(B)=528P(A) \times P(B) = \frac{5}{28}, they are equal.
  5. Confirm Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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