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In an experiment, the probability that event AA occurs is 58\frac{5}{8}, the probability that event BB occurs is 25\frac{2}{5}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 58\frac{5}{8}, the probability that event BB occurs is 25\frac{2}{5}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(58)×(25)P(A) \times P(B) = \left(\frac{5}{8}\right) \times \left(\frac{2}{5}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(58)×(25)=1040(\frac{5}{8}) \times (\frac{2}{5}) = \frac{10}{40}
  4. Simplify Fraction: Simplify the fraction 1040\frac{10}{40} to its lowest terms.\newline1040=14\frac{10}{40} = \frac{1}{4}
  5. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=18P(A \text{ and } B) = \frac{1}{8}\newlineP(A)×P(B)=14P(A) \times P(B) = \frac{1}{4}\newlineSince 18\frac{1}{8} is not equal to 14\frac{1}{4}, events AA and BB are not independent.

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