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In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 35\frac{3}{5}, and the probability that events AA and BB both occur is 16\frac{1}{6}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 35\frac{3}{5}, and the probability that events AA and BB both occur is 16\frac{1}{6}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(59)×(35)P(A) \times P(B) = \left(\frac{5}{9}\right) \times \left(\frac{3}{5}\right)
  3. Perform Multiplication: Now, do the multiplication.\newline(59)×(35)=1545(\frac{5}{9}) \times (\frac{3}{5}) = \frac{15}{45}
  4. Simplify Fraction: Simplify the fraction 1545\frac{15}{45} to its lowest terms.\newline1545=13\frac{15}{45} = \frac{1}{3}
  5. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=16P(A \text{ and } B) = \frac{1}{6}\newlineP(A)×P(B)=13P(A) \times P(B) = \frac{1}{3}\newlineSince 16\frac{1}{6} is not equal to 13\frac{1}{3}, events AA and BB are not independent.

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