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In an experiment, the probability that event AA occurs is 38\frac{3}{8}, the probability that event BB occurs is 45\frac{4}{5}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 38\frac{3}{8}, the probability that event BB occurs is 45\frac{4}{5}, and the probability that events AA and BB both occur is 15\frac{1}{5}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Use Conditional Probability Formula: To find the probability that AA occurs given that BB occurs, we use the formula for conditional probability: P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate P(A and B)P(A \text{ and } B): We know P(A and B)=15P(A \text{ and } B) = \frac{1}{5} and P(B)=45P(B) = \frac{4}{5}.
  3. Calculate P(AB)P(A|B): Now, we calculate P(AB)=15/45P(A|B) = \frac{1}{5} / \frac{4}{5}.
  4. Simplify the Fraction: Simplify the fraction by multiplying the numerator by the reciprocal of the denominator: P(AB)=15×54P(A|B) = \frac{1}{5} \times \frac{5}{4}.
  5. Perform the Multiplication: Perform the multiplication: P(AB)=14P(A|B) = \frac{1}{4}.

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