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In an experiment, the probability that event AA occurs is 89\frac{8}{9} and the probability that event BB occurs is 16\frac{1}{6}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 89\frac{8}{9} and the probability that event BB occurs is 16\frac{1}{6}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.
  1. Calculate P(A and B)P(A \text{ and } B): Calculate P(A and B)P(A \text{ and } B) using the formula for independent events: P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B). So we got P(A and B)=89×16P(A \text{ and } B) = \frac{8}{9} \times \frac{1}{6}.
  2. Do the multiplication: Do the multiplication: 89×16=854\frac{8}{9} \times \frac{1}{6} = \frac{8}{54}.
  3. Simplify the fraction: Simplify the fraction 854\frac{8}{54} by dividing both numerator and denominator by their greatest common divisor, which is 22. So, 854\frac{8}{54} simplifies to 427\frac{4}{27}.

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