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In an experiment, the probability that event AA occurs is 67\frac{6}{7} and the probability that event BB occurs is 18\frac{1}{8}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 67\frac{6}{7} and the probability that event BB occurs is 18\frac{1}{8}. If AA and BB are independent events, what is the probability that AA and BB both occur?\newlineSimplify any fractions.
  1. Calculate P(A and B)P(A \text{ and } B): Calculate P(A and B)P(A \text{ and } B) for independent events AA and BB: P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B).
  2. Substitute given probabilities: Substitute the given probabilities into the formula: P(A and B)=(67)×(18)P(A \text{ and } B) = \left(\frac{6}{7}\right) \times \left(\frac{1}{8}\right).
  3. Perform multiplication: Perform the multiplication to find P(A and B)P(A \text{ and } B): 67×18=656\frac{6}{7} \times \frac{1}{8} = \frac{6}{56}.
  4. Simplify fraction: Simplify the fraction 656\frac{6}{56} to its lowest terms.
  5. Divide by greatest common divisor: Divide both numerator and denominator by the greatest common divisor, which is 22: 656=328\frac{6}{56} = \frac{3}{28}.

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