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In a newspaper, it was reported that yearly robberies in Springfield were down 
25% to 108 in 2013 from 2012. How many robberies were there in Springfield in 2012?
Answer:

In a newspaper, it was reported that yearly robberies in Springfield were down 25% 25 \% to 108108 in 20132013 from 20122012. How many robberies were there in Springfield in 20122012?\newlineAnswer:

Full solution

Q. In a newspaper, it was reported that yearly robberies in Springfield were down 25% 25 \% to 108108 in 20132013 from 20122012. How many robberies were there in Springfield in 20122012?\newlineAnswer:
  1. Identify Given Information: Let's identify the given information and what we need to find. We know that the number of robberies in 20132013 was 108108, which is 25%25\% less than the number of robberies in 20122012. We need to find the original number of robberies in 20122012 before the decrease.
  2. Calculate Percentage Decrease: To find the number of robberies in 20122012, we need to understand that a 25%25\% decrease means that the number of robberies in 20132013 is 75%75\% of the number of robberies in 20122012. Let's represent the number of robberies in 20122012 as 'RR'.
  3. Set Up Equation: We can set up the equation: 75%75\% of R=108R = 108. To solve for RR, we need to convert the percentage to a decimal. So, 75%75\% becomes 0.750.75. The equation is now: 0.75×R=1080.75 \times R = 108.
  4. Solve for R: To find R, we divide both sides of the equation by 0.750.75. So, R=1080.75R = \frac{108}{0.75}.
  5. Final Result: Performing the division, we get R=144R = 144. This means there were 144144 robberies in Springfield in 20122012.

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