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In a newspaper, it was reported that yearly robberies in Springfield were down 
20% to 108 in 2012 from 2011. How many robberies were there in Springfield in 2011?
Answer:

In a newspaper, it was reported that yearly robberies in Springfield were down 20% 20 \% to 108108 in 20122012 from 20112011. How many robberies were there in Springfield in 20112011?\newlineAnswer:

Full solution

Q. In a newspaper, it was reported that yearly robberies in Springfield were down 20% 20 \% to 108108 in 20122012 from 20112011. How many robberies were there in Springfield in 20112011?\newlineAnswer:
  1. Understand Robbery Decrease: To find the number of robberies in 20112011, we need to understand that the number of robberies in 20122012 is 80%80\% of the number in 20112011, since they have decreased by 20%20\%. Let's denote the number of robberies in 20112011 as RR.
  2. Equation Setup: We know that 108108 robberies in 20122012 are 80%80\% of the robberies in 20112011. So we can write the equation: 0.80×R=1080.80 \times R = 108.
  3. Solve for R: To find R, we need to divide both sides of the equation by 0.800.80. So, R=1080.80R = \frac{108}{0.80}.
  4. Final Result: Performing the division, we get R=135R = 135. This means there were 135135 robberies in Springfield in 20112011.

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