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In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 135 , and then went up by 
20% in 2011 . How many robberies were there in Springfield in 2011?
Answer:

In a newspaper, it was reported that the number of yearly robberies in Springfield in 20102010 was 135135 , and then went up by 20% 20 \% in 20112011 . How many robberies were there in Springfield in 20112011?\newlineAnswer:

Full solution

Q. In a newspaper, it was reported that the number of yearly robberies in Springfield in 20102010 was 135135 , and then went up by 20% 20 \% in 20112011 . How many robberies were there in Springfield in 20112011?\newlineAnswer:
  1. Understand Problem: Understand the problem and identify the given values.\newlineWe know that the number of robberies in Springfield in 20102010 was 135135. We also know that there was a 20%20\% increase in the number of robberies in 20112011.
  2. Calculate Increase: Calculate the increase in the number of robberies.\newlineTo find the increase, we multiply the number of robberies in 20102010 by the percentage increase (expressed as a decimal).\newlineIncrease = 135135 robberies ×20%\times 20\% (or 0.200.20 as a decimal).
  3. Perform Calculation: Perform the calculation for the increase. Increase=135×0.20=27\text{Increase} = 135 \times 0.20 = 27 robberies.
  4. Total Robberies 20112011: Calculate the total number of robberies in 20112011.\newlineTo find the total number of robberies in 20112011, we add the increase to the number of robberies in 20102010.\newlineTotal robberies in 20112011 = 135135 robberies + 2727 robberies.
  5. Perform Calculation: Perform the calculation for the total number of robberies in 20112011.\newlineTotal robberies in 20112011 = 135+27=162135 + 27 = 162 robberies.

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