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Trigonometric Graphs
Word problem involving a sine or cosine function: Problem type 1
Jameson
Español
An object moves in simple harmonic motion with amplitude 
13cm and period 0.25 seconds. At time 
t=0 seconds, its displacement 
d from rest is 
0cm, and initially it moves in a positive direction.
Give the equation modeling the displacement 
d as a function of time 
t.

d=

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2:11 PM

4//22//2024

Import favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Graphs\newlineWord problem involving a sine or cosine function: Problem type 11\newlineJameson\newlineEspañol\newlineAn object moves in simple harmonic motion with amplitude 13 cm 13 \mathrm{~cm} and period 00.2525 seconds. At time t=0 t=0 seconds, its displacement d d from rest is 0 cm 0 \mathrm{~cm} , and initially it moves in a positive direction.\newlineGive the equation modeling the displacement d d as a function of time t t .\newlined= d= \newline \square \newline \square \newlineExplanation\newlineCheck\newline(C) 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search\newline59F 59^{\circ} \mathrm{F} \newline(11))\newline22:1111 PM\newline4/22/2024 4 / 22 / 2024

Full solution

Q. Import favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Graphs\newlineWord problem involving a sine or cosine function: Problem type 11\newlineJameson\newlineEspañol\newlineAn object moves in simple harmonic motion with amplitude 13 cm 13 \mathrm{~cm} and period 00.2525 seconds. At time t=0 t=0 seconds, its displacement d d from rest is 0 cm 0 \mathrm{~cm} , and initially it moves in a positive direction.\newlineGive the equation modeling the displacement d d as a function of time t t .\newlined= d= \newline \square \newline \square \newlineExplanation\newlineCheck\newline(C) 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search\newline59F 59^{\circ} \mathrm{F} \newline(11))\newline22:1111 PM\newline4/22/2024 4 / 22 / 2024
  1. Identify Amplitude and Period: Identify the amplitude (AA) and period (TT) of the simple harmonic motion. The amplitude is 13cm13\,\text{cm} and the period is 0.25seconds0.25\,\text{seconds}.
  2. Recall General Equation: Recall the general form of the equation for simple harmonic motion, which is d(t)=Asin(2πt/T+φ)d(t) = A \cdot \sin(2\pi \cdot t / T + \varphi), where φ\varphi is the phase shift.
  3. Determine Phase Shift: Since the object starts at rest and moves in a positive direction at t=0t=0, the phase shift φ\varphi is π2\frac{\pi}{2} radians.
  4. Substitute Values: Substitute the values of AA, TT, and φ\varphi into the equation. d(t)=13×sin(2π×t/0.25+π/2)d(t) = 13 \times \sin(2\pi \times t / 0.25 + \pi/2).
  5. Simplify Equation: Simplify the equation by calculating the coefficient of tt inside the sine function. The coefficient is 2π0.25=8π\frac{2\pi}{0.25} = 8\pi.
  6. Write Final Displacement Function: Write the final equation for the displacement dd as a function of time tt. d(t)=13sin(8πt+π2)d(t) = 13 \cdot \sin(8\pi \cdot t + \frac{\pi}{2}).

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