Iiva Certain eximintion, tz candidales opzexed mathentics, 64 offered finglish and G2 French. 18 offered both mathemates and Inghsh, 24 mathematers and French and 20 - English and prench. 8 Gudidates eqpered all the three sublects. How many Cundidates Where there For the ceamintion?
Q. Iiva Certain eximintion, tz candidales opzexed mathentics, 64 offered finglish and G2 French. 18 offered both mathemates and Inghsh, 24 mathematers and French and 20 - English and prench. 8 Gudidates eqpered all the three sublects. How many Cundidates Where there For the ceamintion?
Denote Candidates: Let's denote the number of candidates who offered mathematics as M, English as E, and French as G. According to the problem, we have the following information:- M candidates offered mathematics.- 64 candidates offered English.- G2 candidates offered French.- 18 candidates offered both mathematics and English.- 24 candidates offered both mathematics and French.- 20 candidates offered both English and French.- 8 candidates offered all three subjects.We will use the principle of inclusion-exclusion to find the total number of candidates (E0). The formula is:E1Where:- M = candidates who offered mathematics- E = candidates who offered English- G = candidates who offered French- E5 = candidates who offered both mathematics and English- E6 = candidates who offered both mathematics and French- E7 = candidates who offered both English and French- E8 = candidates who offered all three subjectsWe know E9 and G0. However, we do not have the values for M and G. We need to find these values using the given information.
Find Candidates Offering Subjects: First, let's find the total number of candidates who offered both mathematics and another subject. We have:ME+MF−MEF=18+24−8ME+MF−MEF=42−8ME+MF−MEF=34This means that 34 candidates offered mathematics and at least one other subject, excluding those who offered all three.
Express Total Candidates: Next, let's find the total number of candidates who offered both English and another subject. We have:ME+EF−MEF=18+20−8ME+EF−MEF=38−8ME+EF−MEF=30This means that 30 candidates offered English and at least one other subject, excluding those who offered all three.
Find Values for M and G_2: Now, let's find the total number of candidates who offered both French and another subject. We have:MF+EF−MEF=24+20−8MF+EF−MEF=44−8MF+EF−MEF=36This means that 36 candidates offered French and at least one other subject, excluding those who offered all three.
Problem Statement Missing: We can now express the total number of candidates T as:T=M+64+G2−(34+30+36)+8T=M+64+G2−100+8T=M+G2−28We still need to find the values for M and G2 to solve for T.
Problem Statement Missing: We can now express the total number of candidates T as:T=M+64+G2−(34+30+36)+8T=M+64+G2−100+8T=M+G2−28We still need to find the values for M and G2 to solve for T.The problem does not provide explicit values for M and G2, and without these values, we cannot determine the total number of candidates T. It seems there is a mistake or missing information in the problem statement, as we cannot solve for T with the given information.