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III. Find the missing value in the ordere\newline1010. \newliney=−3x−10y=-3x-10; let \newliney=−16y=-16

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Full solution

Q. III. Find the missing value in the ordere\newline1010. \newliney=−3x−10y=-3x-10; let \newliney=−16y=-16
  1. Substitute and Solve: To find the value of xx when y=−16y = -16, we need to substitute yy with −16-16 in the equation y=−3x−10y = -3x - 10 and solve for xx.\newlineCalculation: −16=−3x−10-16 = -3x - 10
  2. Addition to Isolate: Next, we add 1010 to both sides of the equation to isolate the term with xx on one side.\newlineCalculation: −16+10=−3x−10+10-16 + 10 = -3x - 10 + 10\newlineThis simplifies to: −6=−3x-6 = -3x
  3. Divide to Solve: Now, we divide both sides of the equation by −3-3 to solve for xx.\newlineCalculation: (−6)/(−3)=(−3x)/(−3)(-6) / (-3) = (-3x) / (-3)\newlineThis simplifies to: x=2x = 2

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