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If
y=(x-2)(x-1)(2x^(2)+3)+4, what is the value of
y when
x=1 ?

If $y=(x-2)(x-1)\left(2 x^{2}+3\right)+4$ , what is the value of $y$ when $x=1$ ?

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Evaluate expression when two complex numbers are given

Full solution

Q. If

y=(x-2)(x-1)\left(2 x^{2}+3\right)+4

, what is the value of

y

when

x=1

?

Substitute $x=1$ : We are given the function $y=(x-2)(x-1)(2x^{2}+3)+4$ and we need to find the value of $y$ when $x=1$ . First, substitute $x=1$ into the function. $y=(1-2)(1-1)(2\cdot 1^{2}+3)+4$
Calculate value of terms: Now, calculate the value of each term in the expression. $\newline$ $(1-2) = -1$ $\newline$ $(1-1) = 0$ $\newline$ $(2\cdot1^{2}+3) = 2\cdot1 + 3 = 2 + 3 = 5$
Product of first three terms: Since one of the terms $(1-1)$ is zero, the product of the first three terms will be zero. $(-1) \times 0 \times 5 = 0$
Add constant term: Finally, add the constant term $4$ to the product of the first three terms. $\newline$ $0 + 4 = 4$

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