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If yy varies inversely with xx and y=5y = 5 when x=8x = 8, find yy when x=2x = 2. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____

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Q. If yy varies inversely with xx and y=5y = 5 when x=8x = 8, find yy when x=2x = 2. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____
  1. Define Inverse Variation: Inverse variation means y=kxy = \frac{k}{x}. We need to find kk using the given values y=5y = 5 and x=8x = 8.
  2. Substitute Values: Substitute y=5y = 5 and x=8x = 8 into the equation to get 5=k85 = \frac{k}{8}.
  3. Solve for Constant: Multiply both sides by 88 to solve for kk: 5×8=k5 \times 8 = k.
  4. Write Equation with Constant: k=40k = 40. Now we have the constant of variation.
  5. Find yy for x=2x=2: Write the inverse variation equation with kk: y=40xy = \frac{40}{x}.
  6. Find yy for x=2x=2: Write the inverse variation equation with kk: y=40xy = \frac{40}{x}.Find yy when x=2x = 2 by substituting x=2x = 2 into y=40xy = \frac{40}{x}.
  7. Find yy for x=2x=2: Write the inverse variation equation with kk: y=40xy = \frac{40}{x}.Find yy when x=2x = 2 by substituting x=2x = 2 into y=40xy = \frac{40}{x}.y=402y = \frac{40}{2}.
  8. Find yy for x=2x=2: Write the inverse variation equation with kk: y=40xy = \frac{40}{x}.Find yy when x=2x = 2 by substituting x=2x = 2 into y=40xy = \frac{40}{x}.y=402y = \frac{40}{2}.y=20y = 20. So when x=2x = 2, y=20y = 20.

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