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If yy varies inversely with xx and y=5y = -5 when x=15x = 15, find yy when x=3x = -3. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____

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Q. If yy varies inversely with xx and y=5y = -5 when x=15x = 15, find yy when x=3x = -3. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____
  1. Identify Inverse Variation: Inverse variation means y=kxy = \frac{k}{x}. We need to find kk using the given values y=5y = -5 when x=15x = 15.
  2. Plug in Values: Plug in the values: 5=k15-5 = \frac{k}{15}. Now solve for kk by multiplying both sides by 1515.
  3. Solve for k: 5×15=k–5 \times 15 = k. So, k=75k = –75.
  4. Finalize Equation: Now we have the inverse variation equation: y=75xy = \frac{-75}{x}. Let's find yy when x=3x = -3.
  5. Substitute xx: Substitute 3–3 for xx: y=753y = \frac{–75}{–3}.
  6. Calculate yy: Calculate yy: y=25y = 25. Oops, that's not right, I divided wrong.

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