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If yy varies inversely with xx and y=3y = 3 when x=2x = 2, find yy when x=1x = 1. Write and solve an inverse variation equation to find the answer. y=y = _____

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Q. If yy varies inversely with xx and y=3y = 3 when x=2x = 2, find yy when x=1x = 1. Write and solve an inverse variation equation to find the answer. y=y = _____
  1. Identify general form: Given that yy varies inversely with xx. Identify the general form of inverse variation. In inverse variation, variables change in opposite directions. Inverse variation: y=kxy = \frac{k}{x}
  2. Substitute values in equation: We know that y=3y = 3 when x=2x = 2. Choose the equation after substituting the values in y=kxy = \frac{k}{x}. Substitute 22 for xx and 33 for yy in y=kxy = \frac{k}{x}. 3=k23 = \frac{k}{2}
  3. Solve for k: We found:\newline3=k23 = \frac{k}{2}\newlineSolve the equation to find the value of k.\newlineTo isolate k, multiply both sides by 22.\newline3×2=(k2)×23 \times 2 = \left(\frac{k}{2}\right) \times 2\newline6=k6 = k
  4. Write inverse variation equation: We have:\newlinek=6k = 6\newlineWrite the inverse variation equation in the form of y=kxy = \frac{k}{x}.\newlineSubstitute k=6k = 6 in y=kxy = \frac{k}{x}.\newliney=6xy = \frac{6}{x}
  5. Find yy for x=1x=1: Inverse variation equation:\newliney=6xy = \frac{6}{x}\newlineFind yy when x=1x = 1.\newlineSubstitute 11 for xx in y=6xy = \frac{6}{x}.\newliney=61y = \frac{6}{1}\newliney=6y = 6

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